Question
Download Solution PDFA ball is dropped from a height of 10 m. It strikes the ground and rebounds up to a height of 2.5 m. During the collision, the per cent loss in the kinetic energy is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF- In condition of free fall, the potential energy is converted into kinetic energy (K.E)
- According to the law of conservation of mechanical energy:
- Initial kinetic energy = Potential Energy = mgh
- Final kinetic energy = mgh1
- Change in kinetic energy = mg (h-h1)
- Percentage change in kinetic energy = \(\frac{{{\rm{mg}}\left( {{\rm{h}} - {\rm{\;h}}1} \right)}}{{{\rm{mgh}}}}\) × 100 = [(7.5/10) × (100)] = 75%.
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