A bar of length 2.5 m is subjected to an axial pull of 200 kN, if the change in length due to the applied load is 5 mm, calculate the linear strain experienced by the bar in the direction of the applied load.

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DDA JE Civil 01 Apr 2023 Shift 1 Official Paper
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  1. 0.00725
  2. 0.002
  3. 0.0250
  4. 0.25

Answer (Detailed Solution Below)

Option 2 : 0.002
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Explanation:

Linear strain is defined as the change in length divided by the original length.

The change in length is given as 5 mm which is equivalent 5/1000 = 0.005 m (since 1 m = 1000 mm)

The original length is given as 2.5 m.

So, the linear strain (ε) can be calculated as:

ε = (Change in length) / (Original length) = 0.005 m / 2.5 m = 0.002

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