Question
Download Solution PDFA bar of length 2.5 m is subjected to an axial pull of 200 kN, if the change in length due to the applied load is 5 mm, calculate the linear strain experienced by the bar in the direction of the applied load.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Linear strain is defined as the change in length divided by the original length.
The change in length is given as 5 mm which is equivalent 5/1000 = 0.005 m (since 1 m = 1000 mm)
The original length is given as 2.5 m.
So, the linear strain (ε) can be calculated as:
ε = (Change in length) / (Original length) = 0.005 m / 2.5 m = 0.002
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