A metal block of mass 5 kg and temperature 100°C cools to a temperature of 50°C. The specific heat of the metal is 600 J/kg°C and its density is 8000 kg/m³. The heat lost by the metal block is

Question

Question

This question was previously asked in

ISRO VSSC Technical Assistant Mechanical 14 July 2021 Official Paper

Answer 1

Concept:

The quantity of heat required to raise the temperature of one gram of a substance by one Celsius degree is known as Specific Heat.

Mathematically,

Heat Energy is given by

Q = m c Δ T

where m is mass, c is specific heat and Δ T is temperature difference

Calculation:
Given:

m = 5 kg, T1 = 100°C,T2 = 50°C and c = 600 J/kg°C

Q = m c ΔT

∴ Q = 5×600× (100 - 50) = 150000 J = 150 KJ