Question
Download Solution PDFA single cylinder, 4-stroke cycle engine is fitted with a rope brake. The diameter of the brake wheel is 600 mm and the rope diameter is 26 mm. The dead weight on the brake is 200 N and the spring balance reads 30 N. If the engine runs at 450 rpm, what will be the brake power of the engine?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Break power: \(bp = \frac{{\pi DN\left( {W - S} \right)}}{{60}}watt\)
Where D = effective brake drum diameter
N = rpm
W = dead weight
S = spring balance reading
Calculation:
Given, D = 600 + 26 = 626 mm
N = 450 rpm
W = 200 N
S = 30 N
\(∴ bp = \frac{{3.14 \times 0.626 \times 450 \times \left( {200 - 30} \right)}}{{60,000}}\)
∴ bp = 2.5062 kWLast updated on May 28, 2025
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