A stone of mass “m” at the end of a string of length “L” is whirled in a vertical circle at a constant speed. The tension in the string will be maximum when the stone is

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SSC JE ME Previous Paper 8 (Held on: 27 October 2020 Evening)
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  1. At the top of the circle
  2. half way down from the top
  3. at the bottom of the circle
  4. quarter way down the top

Answer (Detailed Solution Below)

Option 3 : at the bottom of the circle
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Detailed Solution

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Concept:

F1 J.K 2.6.20 Pallavi D1at,

Let the string makes an angle θ with the positive vertical axis, then tension is given as 

\(T = -\;mg\cos θ + \frac{{m{v^2}}}{r}\)

At bottom of the circle, string makes an angle 180° with a positive vertical axis,

⇒ θ = 180° ⇒  cos θ = -1

⇒ \(T = mg + \frac{{m{v^2}}}{r}\)

Therefore, at the bottom of the circle, centrifugal force and the weight are added.

So, it will be the point of maximum tension.

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