Question
Download Solution PDFAn object is placed on the principal axis of a lens of power -10.0 D, at a distance of 30 cm from it. The image is formed at a distance of _______ from the lens and is ______.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is 7.5 cm; virtual.
Key Points
- The power of the lens is -10.0 D, which indicates it is a diverging lens.
- The formula for the focal length (f) of a lens is given by f = 1/P, where P is the power. Thus, f = -0.1 m or -10 cm.
- Using the lens formula (1/f = 1/v - 1/u), where u is the object distance (in this case, -30 cm), we can find the image distance (v).
- Substituting the given values, we get 1/(-10) = 1/v - 1/(-30). Solving this gives v = -7.5 cm, indicating the image is virtual.
- Thus, the image is formed at a distance of 7.5 cm from the lens and is virtual.
Additional Information
- Lens Power
- The power of a lens is measured in diopters (D), and it is the reciprocal of the focal length in meters.
- A positive power indicates a converging lens, while a negative power indicates a diverging lens.
- Lens Formula
- The lens formula is 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance.
- This formula helps in determining the position and nature (real or virtual) of the image formed by the lens.
- Virtual Image
- A virtual image is formed when the outgoing rays from a point on the object appear to diverge from a point behind the lens.
- Virtual images cannot be projected on a screen as they are formed by diverging rays.
- Diverging Lens
- A diverging lens spreads out light rays that are initially parallel, causing them to diverge away from a common point.
- These lenses are thinner at the center and thicker at the edges.
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