An object is placed on the principal axis of a lens of power -10.0 D, at a distance of 30 cm from it. The image is formed at a distance of _______ from the lens and is ______.

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AAI Junior Assistant (Fire Service) Official Paper (Held On: 15 Nov, 2022 Shift 2)
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  1. 7.5 cm; real
  2. 7.5 cm; virtual
  3. 15.0 cm; real
  4. 15.0 cm; virtual

Answer (Detailed Solution Below)

Option 2 : 7.5 cm; virtual
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The correct answer is 7.5 cm; virtual.

Key Points

  • The power of the lens is -10.0 D, which indicates it is a diverging lens.
  • The formula for the focal length (f) of a lens is given by f = 1/P, where P is the power. Thus, f = -0.1 m or -10 cm.
  • Using the lens formula (1/f = 1/v - 1/u), where u is the object distance (in this case, -30 cm), we can find the image distance (v).
  • Substituting the given values, we get 1/(-10) = 1/v - 1/(-30). Solving this gives v = -7.5 cm, indicating the image is virtual.
  • Thus, the image is formed at a distance of 7.5 cm from the lens and is virtual.

Additional Information

  • Lens Power
    • The power of a lens is measured in diopters (D), and it is the reciprocal of the focal length in meters.
    • A positive power indicates a converging lens, while a negative power indicates a diverging lens.
  • Lens Formula
    • The lens formula is 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance.
    • This formula helps in determining the position and nature (real or virtual) of the image formed by the lens.
  • Virtual Image
    • A virtual image is formed when the outgoing rays from a point on the object appear to diverge from a point behind the lens.
    • Virtual images cannot be projected on a screen as they are formed by diverging rays.
  • Diverging Lens
    • A diverging lens spreads out light rays that are initially parallel, causing them to diverge away from a common point.
    • These lenses are thinner at the center and thicker at the edges.
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