As per Gay Lussac’s law, which one is the correct statement

P_T = Pressure at temperature T°C;

P₀ = Pressure at temperature 0°C;

Concept:

Gay-Lussac's law

P1 × T2 = P2 × T1

where P1 = the initial pressure, T1 = the initial temperature, P2 = the final pressure, T2 = the final temperature.

Calculation:

Given:

P1 = P₀, T1 = 0°C = 273 K, P2 = P_T, and  T2 = T°C = (T + 273) k

Gay-Lussac's law

P1 × T2 = P2 × T1

P₀ × (T + 273) = P_T × 273

\({P_T}={P_0}\left( {1 + \frac{T}{{273}}} \right)\)

Additional Information

Gay-Lussac’s law

The pressure exerted by a gas varies directly with the absolute temperature of the gas where the gas is having fixed mass and the constant volume.

P ∝ T ;\( {P\over T} = k\)

where P is the pressure exerted by the gas, T is the absolute temperature of the gas, k is a constant.

\({P_1\over T_1} = k \)(initial condition), \({P_2\over T_2} = k \) (final condition)

∴ \({P_1\over T_1} = {P_2\over T_2}=k\)  or P1 × T2 = P2 × T1