Consider the following reaction:

2HgO \( \stackrel{\Delta}{\longrightarrow} \) 2Hg + O2

The respective state of HgO, Hg and O2 in the above reaction is

This question was previously asked in
UPSC NDA-II (General Ability) Official Paper-I (Held On: 03 Sept, 2023)
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  1. Liquid, solid, gas
  2. Solid, solid, gas
  3. Liquid, solid, liquid
  4. Solid, liquid, gas

Answer (Detailed Solution Below)

Option 4 : Solid, liquid, gas
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Detailed Solution

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The correct answer is Solid, liquid, gas.

Key Points

  • In the given reaction:
    • 2HgO \( \stackrel{\Delta}{\longrightarrow} \) 2Hg + O2
  • HgO is mercury(II) oxide (red mercuric oxide) and is a solid (s) before the reaction.
  • Hg is mercury and is in a liquid (l) state after the reaction.
  • O2 ​ is oxygen gas and is in a gaseous (g) state after the reaction.
  • Therefore, the respective states are:
    • 2HgO (s) \( \stackrel{\Delta}{\longrightarrow} \) Hg (l) + O2 (g)
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