Question
Download Solution PDFFor a CE configuration, the transistor supply voltage is 12 V. The load resistance is 900 Ω. The voltage drop across load resistance is 0.9 V. The value of collector-emitter voltage is ___________.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConfiguration of BJT:
A BJT is a 3-terminal device i.e. base, emitter, and collector.
A BJT can operate in three configurations i.e. common emitter, common collector, and common base.
|
Configuration |
Input |
Output |
Ground |
|
Common emitter |
Base |
Collector |
Emitter |
|
Common collector |
Base |
Emitter |
Collector |
|
Common base |
Emitter |
Collector |
Base |
Circuit diagram of CE configuration
Applying KVL at the output side:
\(V_{cc}=V_L+V_{ce}\)
where, Vcc = Supply voltage
VL = Voltage drop across the load resistance
Vce = Collector emitter voltage
Calculation
Given, Vcc = 12 V
VL = 0.9 V
\(12=0.9+V_{ce}\)
Vce = 11.1 V
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