Gravitational law of attraction is given by:

This question was previously asked in
JKSSB JE CE 2021 Official Paper Shift 1 (Held on 27 Oct 2021)
View all JKSSB JE Papers >
  1. F= 2G(m1+m2)/r2
  2. F= r2/2G(m1+m2)
  3. F= G(m1× m2)/r2
  4. F= r2/ G(m1+m2)

Answer (Detailed Solution Below)

Option 3 : F= G(m1× m2)/r2
Free
ST 1: JKSSB JE - Surveying
20 Qs. 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

Concept:

  • Newton’s law of gravitation: According to this law- When two objects having some masses are placed at a certain distance then the gravitational force is directly proportional to the product of masses and it is inversely proportional to the square of the distance between them.

 

Where G is gravitational constant, r is the distance between two masses, mand mare the masses.

Latest JKSSB JE Updates

Last updated on Jun 23, 2025

-> JKSSB JE application form correction facility has been started. Candidates can make corrections in the JKSSB recruitment 2025 form from June 23 to 27. 

-> JKSSB Junior Engineer recruitment exam date 2025 for Civil and Electrical Engineering has been released on its official website. 

-> JKSSB JE exam will be conducted on 10th August (Civil), and on 27th July 2025 (Electrical).

-> JKSSB JE recruitment 2025 notification has been released for Civil Engineering. 

-> A total of 508 vacancies has been announced for JKSSB JE Civil Engineering recruitment 2025. 

-> JKSSB JE Online Application form will be activated from 18th May 2025 to 16th June 2025 

-> Candidates who are preparing for the exam can access the JKSSB JE syllabus PDF from official website of JKSSB.

-> The candidates can check the JKSSB JE Previous Year Papers to understand the difficulty level of the exam.

-> Candidates also attempt the JKSSB JE Mock Test which gives you an experience of the actual exam.

More Gravitation Questions

Hot Links: teen patti royal - 3 patti teen patti win teen patti list teen patti master apk best