तल 2x - y - 2z + 1 = 0 और 3x - 4y + 5z - 3 = 0 के बीच का कोण क्या है?

  1. π / 6
  2. π / 4
  3. π / 3
  4. π / 2

Answer (Detailed Solution Below)

Option 4 : π / 2
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संकल्पना:

माना कि a1x + b1y + c1z + d= 0 और a2x + b2y + c2z + d2 = 0 कोई भी दो तल है, तो उनके बीच का कोण निम्न दिया गया है,

\(\rm \cos \theta = \left | \frac{a_{1}a_{2}+b_{1}b_{2}+c_{1}c_{2}}{\sqrt{a_{1}^2+b_{1}^2+c_{1}^2}\times\sqrt{a_{2}^2+b_{2}^2+c_{2}^2}} \right |\)

गणना:

दिए गए तल 2x - y - 2z + 1 = 0 और 3x - 4y + 5z - 3 = 0 हैं। 

हम जानते हैं कि, a1x + b1y + c1z + d= 0 और a2x + b2y + c2z + d2 = 0 कोई भी दो तल है, तो उनके बीच का कोण निम्न दिया गया है,

\(\rm \cos \theta = \left | \frac{a_{1}a_{2}+b_{1}b_{2}+c_{1}c_{2}}{\sqrt{a_{1}^2+b_{1}^2+c_{1}^2}\times\sqrt{a_{2}^2+b_{2}^2+c_{2}^2}} \right |\)

यहाँ, a= 2, a= 3, b= - 1, b= - 4, c= - 2, c= 5.

\(\rm \cos \theta = \left | \frac{(2)(3)+(-1)(-4)+(-2)(5)}{\sqrt{2^2+(-1)^2+(-2)^2}\times\sqrt{3^2+(-4)^2+5^2}} \right |\)

\(\cos\theta = 0\)

⇒ \(\rm \theta = \frac{\pi}{2}\)

अतः तल 2x - y - 2z + 1 = 0 और 3x - 4y + 5z - 3 = 0 के बीच का कोण \(\frac{\pi}{2}\) है। 

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