Question
Download Solution PDFIf 25th February, 2008 was a Monday, then what was the day of 15th March, 2008?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven: 25th February, 2008 was a Monday.
Now,
Number of days remaining in February 2008 = 29 - 25 = 4 days (2008 is a leap year).
Number of days in March 2008 until 15th = 15 days.
Total number of days = 4 + 15 = 19 days.
Number of odd days = 19 ÷ 7 = 2 weeks and 5 odd days.
So, the day of 15th March, 2008 will be Monday + 5 days.
Monday + 1 day = Tuesday
Tuesday + 1 day = Wednesday
Wednesday + 1 day = Thursday
Thursday + 1 day = Friday
Friday + 1 day = Saturday
Hence, the day of 15th March, 2008 was Saturday.
Last updated on Jun 16, 2025
-> The Bihar B.Ed. CET 2025 couselling for admission guidelines is out in the official website.
-> Bihar B.Ed. CET 2025 examination result has been declared on the official website
-> Bihar B.Ed CET 2025 answer key was made public on May 29, 2025. Candidates can log in to the official websitde and download their answer key easily.
-> Bihar CET B.Ed 2025 exam was held on May 28, 2025.
-> The qualified candidates will be eligible to enroll in the 2-year B.Ed or the Shiksha Shastri Programme in universities across Bihar.
-> Check Bihar B.Ed CET previous year question papers to understand the exam pattern and improve your preparation.
-> Candidates can get all the details of Bihar CET B.Ed Counselling from here. Candidates can take the Bihar CET B.Ed mock tests to check their performance.