Question
Download Solution PDFIf A = \(\begin{bmatrix} 2 & 5 \\ 2 & 1 \end{bmatrix}\) and B = \(\begin{bmatrix} 4 & -3 \\ 1 & 5 \end{bmatrix}\)then find |AB|
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Property of determinants:
If A and B are two square matrices then |AB| = |A||B|
Calculation:
Given: A = \(\begin{bmatrix} 2 & 5 \\ 2 & 1 \end{bmatrix}\) and B = \(\begin{bmatrix} 4 & -3 \\ 1 & 5 \end{bmatrix}\)
Now,
|A| = 2 × 1 - 5 × 2 = 2 - 10 = -8
|B| = 4 × 5 - (-3 × 1) = 20 + 3 = 23
As we know that, |AB| = |A||B|
= -8 × 23 = -184
Last updated on Jun 11, 2025
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