Question
Download Solution PDFIf f(2x) = 4x2 + 1, then for how many real values of x will f(2x) be the GM of f(x) and f(4x)?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
f(2x) = 4x2 + 1
⇒f(x) = x2 + 1
⇒ f(4x) = 16x2 + 1
⇒ (4x2 + 1)2 = (x2 + 1) × (16x2 + 1) [f(2x) is GM of f(x) & f(4x)]
⇒ x2 = 0
⇒x = 0
Thus One real value of x is possible
∴ Option (c) is correct.
Last updated on May 30, 2025
->UPSC has released UPSC NDA 2 Notification on 28th May 2025 announcing the NDA 2 vacancies.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced for cycle 2. The written examination will be held on 14th September 2025.
-> Earlier, the UPSC NDA 1 Exam Result has been released on the official website.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.