Question
Download Solution PDFIf the matrix\(\left[ {\begin{array}{*{20}{c}} 1&3&{\lambda + 2}\\ 2&4&8\\ 3&5&{10} \end{array}} \right]\) is singular, then λ equals
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
If a Matrix is singular then its determinant is zero (\(\left| A \right| = 0\))
Calculation:
Given:
Matrix is singular
\(\left| {\begin{array}{*{20}{c}} 1&3&{λ + 2}\\ 2&4&8\\ 3&5&{10} \end{array}} \right|=0\)
1 (40 - 40) - 3(20 - 24) + (λ + 2)(10 - 12) = 0
-3(-4) + (λ + 2)(-2) = 0
12 - 2λ - 4 = 0
8 = 2λ
∴ λ = 4.
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