Question
Download Solution PDFIf there is no slip and the creep in the transmission, then what is the equation for the velocity ratio in the open belt drive?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Velocity Ratio:
The velocity ratio is the ratio of the speed of the driven pulley to that of the driving pulley.
\(Velocity\;Ratio\;(VR)=\frac{N_2}{N_1}=\frac{D_1\;+\;t}{D_2\;+\;t}\)
In the case of belt drive where the slip (S) is present the velocity ratio is given by:
\(Velocity\;Ratio\;(VR)=\frac{N_2}{N_1}=\frac{D_1\;+\;t}{D_2\;+\;t}\left ( \frac{100\;-\;S}{100} \right )\)
In gear and chain drive velocity ratio is given by:
\(Velocity\;Ratio\;(VR)=\frac{N_2}{N_1}=\frac{D_1}{D_2}\)
∵ slip is absent and thickness is very less as compared to the diameter so it can be ignored, ∴ it is constant.
Last updated on May 28, 2025
-> SSC JE ME Notification 2025 will be released on June 30.
-> The SSC JE Mechanical engineering application form will be available from June 30 to July 21.
-> SSC JE 2025 CBT 1 exam for Mechanical Engineering will be conducted from October 2 to 31.
-> SSC JE exam to recruit Junior Engineers in different disciplines under various departments of the Central Government.
-> The selection process of the candidates for the SSC Junior Engineer post consists of Paper I, Paper II, Document Verification, and Medical Examination.
-> Candidates who will get selected will get a salary range between Rs. 35,400/- to Rs. 1,12,400/-.
-> Candidates must refer to the SSC JE Previous Year Papers and SSC JE Civil Mock Test, SSC JE Electrical Mock Test, and SSC JE Mechanical Mock Test to understand the type of questions coming in the examination.