Let f(x) = ax7 + bx3 + cx - 5, where a, b and c are constants. If f(-7) = 7, then f(7) equals

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45th BPSC Prelims (Held in 2002) Official paper
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  1. -17
  2. -7
  3. 14
  4. 17

Answer (Detailed Solution Below)

Option 1 : -17
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The correct answer is option 1.

Given: f(x) = ax7 + bx3 + cx - 5, where a, b and c are constants. If f(-7) = 7,

Calculation:

⇒  f(x) = ax7 + bx3 + cx - 5, 

If f(-7) = 7,

⇒ f(-7) = a(-7)7 + b(-7)3 + c(-7) - 5

⇒ 7 = -77a -73b - 7c - 5

⇒ 7 + 5 = -(77a + 73b + 7c)

⇒ (77a + 73b + 7c) = - 12  ----(1)

⇒ f(7) = a(7)7 + b(7)3 + c(7) - 5, 

⇒ f(7) = 77a + 73b + 7c - 5    -----(2)

From equation (1) and (2)

⇒ f(7) = -12 - 5 = -17

Hence, the value of f(7) will be -17.

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