Let the focal length of an eye-piece be 2.5 cm. For a telescope of magnification 100, the focal length of the objective should be:

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  1. 250 cm
  2. 40 cm
  3. 2.5 × 10-2 cm
  4. 100 cm

Answer (Detailed Solution Below)

Option 1 : 250 cm
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Detailed Solution

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Concept:

  • Magnification produced by a spherical mirror or lens gives the relative extent to which an object is magnified with respect to the object's size.
  • Magnification is the ratio of the objective's focal length to the eyepiece's focal length.

Calculation:

Given data Focal length of eyepiece fE = 2.5 cm

Magnification (M) = 100

fis focal length of objective.

∴ M = \(\frac{f_O}{f_E}\)

∴ 100 = \(\frac{f_O}{2.5}\)

∴ fO = 250 cm

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