Question
Download Solution PDFLet the focal length of an eye-piece be 2.5 cm. For a telescope of magnification 100, the focal length of the objective should be:
This question was previously asked in
RSMSSB Lab Assistant 2016 Official Paper
Answer (Detailed Solution Below)
Option 1 : 250 cm
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RSMSSB Lab Assistant (Science) Paper I: Full Test (Latest Pattern)
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Detailed Solution
Download Solution PDFConcept:
- Magnification produced by a spherical mirror or lens gives the relative extent to which an object is magnified with respect to the object's size.
- Magnification is the ratio of the objective's focal length to the eyepiece's focal length.
Calculation:
Given data Focal length of eyepiece fE = 2.5 cm
Magnification (M) = 100
fO is focal length of objective.
∴ M = \(\frac{f_O}{f_E}\)
∴ 100 = \(\frac{f_O}{2.5}\)
∴ fO = 250 cm
Last updated on May 5, 2025
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