Question
Download Solution PDFMaximum Paramagnetisim shown by the following tripositive ion is :
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Magnetic Behaviour of f-block elements
- La3+ and Lu3+ do not contain any unpaired electrons, hence they do not show paramagnetism. All the other tripositive ions of lanthanides (f-block elements) are paramagnetic.
- Magnetic moments of Ln3+ (tripositive ions of lanthanides) ions are generally well described from Russell - Saunders coupling.
- Magnetic moments can be calculated by Lande's formula
Where
g = Lande's splitting factor.
J = Total angular momentum.
L = Total orbital angular momentum.
S = Total spin angular momentum.
J = L + S ( for more than half-filled orbitals).
J = L - S ( for orbitals less than half-filled).
Explanation:
Since La3+ and Lu3+ do not contain any unpaired electrons, they do not show paramagnetism.
- In the case of Nd+3
The electronic configuration of Nd+3 is given by [Xe]4f3
Here, L = 6
S =
Orbitals are less than half-filled hence J = L - S
J =
Using the values for L, S and J in the formula for g, we get
g =
So, the Magnetic Moment of Nd+3 is
- For Ce+3
The electronic configuration of Ce+3 is given by [Xe]4f1
Here, L = 3
S =
Orbitals are less than half-filled hence J = L - S
Using the values for L,S and J in the formula for g, we get
g =
So, the Magnetic Moment of Ce+3 is
So, Among the given tripositive ions Nd+3 show maximum paramagnetism.
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