Maximum Paramagnetisim shown by the following tripositive ion is :

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RPSC 2nd Grade Science (Held on 1st Nov 2018) Official Paper
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  1. La3+
  2. Lu3+
  3. Nd3+
  4. Ce3+

Answer (Detailed Solution Below)

Option 3 : Nd3+
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RPSC Senior Grade II (Paper I): Full Test 1
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Detailed Solution

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Concept: 

Magnetic Behaviour of f-block elements

  • La3+ and Lu3+ do not contain any unpaired electrons, hence they do not show paramagnetism. All the other tripositive ions of lanthanides (f-block elements) are paramagnetic. 
  • Magnetic moments of Ln3+ (tripositive ions of lanthanides) ions are generally well described from Russell - Saunders coupling.
  • Magnetic moments can be calculated by Lande's formula

Where

= Lande's splitting factor.

= Total angular momentum.

= Total orbital angular momentum.

= Total spin angular momentum.

L + S ( for more than half-filled orbitals).

L - S ( for orbitals less than half-filled).

Explanation:

Since La3+ and Lu3+ do not contain any unpaired electrons, they do not show paramagnetism.

  • In the case of Nd+3

The electronic configuration of Nd+3 is given by [Xe]4f3 

Here, = 6

Orbitals are less than half-filled hence J = L - S

J

Using the values for LS and J in the formula for g, we get 

So, the Magnetic Moment of Nd+3 is 

  • For Ce+3

The electronic configuration of Ce+3 is given by [Xe]4f1 

Here, = 3

Orbitals are less than half-filled hence J = L - S

Using the values for L,S and J in the formula for g, we get 

=  

So, the Magnetic Moment of Ce+3 is 

So, Among the given tripositive ions Nd+3 show maximum paramagnetism.

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