4225 मीटरच्या एका वर्तुळाकार शर्यतीत, X आणि Y एकाच बिंदूपासून आणि त्याच वेळी 54 किमी/तास आणि 63 किमी/ताशी वेगाने सुरू होतात. विरुद्ध दिशेला धावत असताना ते मार्गावर पहिल्यांदा कधी भेटतील?

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SSC CGL 2023 Tier-I Official Paper (Held On: 24 Jul 2023 Shift 2)
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  1. 140 सेकंद
  2. 150 सेकंद
  3. 130 सेकंद
  4. 120 सेकंद

Answer (Detailed Solution Below)

Option 3 : 130 सेकंद
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दिलेले आहे:

X आणि Y एकाच बिंदूपासून आणि एकाच वेळी 54 किमी/तास आणि 63 किमी/ताशी वेगाने सुरू होतात.

अंतर = 4225 मीटर 

वापरलेले सूत्र:

अंतर = सापेक्ष वेग x वेळ

गणना:

विरुद्ध दिशेने दोन्हीचा सापेक्ष वेग = S2 + S1

= 54 + 63 = 117 किमी/तास = 117 * (5/18) = 65/2 मीटर/सेकंद.

तर,

विरुद्ध दिशेने धावताना मार्गावर प्रथमच भेटण्यासाठी त्यांना वेळ लागतो = मार्गाची लांबी / विरुद्ध दिशेने सापेक्ष वेग

= 4225/(65/2) = 130 सेकंद

म्हणून, आवश्यक वेळ 130 सेकंद आहे.

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