Question
Download Solution PDFName the white precipitate formed in the reaction of sodium sulphate and barium chloride.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is Barium sulphate.
Key Points
- Barium sulphate (BaSO₄) is an inorganic compound.
- The white precipitate formed in the reaction between sodium sulphate (Na₂SO₄) and barium chloride (BaCl₂) is barium sulphate (BaSO₄).
- Na2SO4+BaCl2 → BaSO4 (white precipitate)+2NaCl
- Barium sulphate (BaSO₄) is insoluble in water, which causes it to form a white precipitate in this reaction.
- Sodium chloride (NaCl) remains in solution as it is soluble in water.
- Barium sulphate is used in X-ray imaging of the digestive system (barium meals or barium enemas), as it is opaque to X-rays.
Additional Information
- Barium hydroxide (Ba(OH)₂):
- Ba(OH)2 heating → BaO+H2O.
- Barium hydroxide Ba(OH)2 decomposes upon heating to form barium oxide (BaO) and water (H2O).
- Sodium chloride (NaCl):
- Sodium chloride, commonly known as table salt is a chemical compound with the formula NaCl.
- It's made up of sodium (Na) and chlorine (Cl) ions.
- When sodium chloride dissolves in water, it dissociates into its constituent ions.
- NaCl(s)→Na+(aq)+Cl−(aq).
- Sodium oxide(Na2O):
- Sodium oxide is a chemical compound with the formula Na₂O.
- It’s an ionic compound composed of sodium (Na) and oxygen (O).
- Sodium oxide is typically formed by the direct reaction of sodium metal with oxygen.
- 4Na(s)+O2(g)→2Na2O(s).
Last updated on Jun 16, 2025
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