Question
Download Solution PDFNumber of bricks of size 20 cm × 10 cm × 10 cm required for 100 cubic metres of masonry wall is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Nominal size of brick = 20 cm × 10 cm × 10 cm ( with mortar)
Calculation:
Nominal size of brick = 20 cm × 10 cm × 10 cm ( with mortar)
So, number of bricks for one cubic meter (1 m3) of brick masonary = \(\frac{{1{m^3}}}{{0.2m \times 0.1m \times 0.1m}}\) = 500
For 100 m3 = 500 x 100 = 50,000
Last updated on Jun 4, 2025
-> OSSC JE Preliminary Fiinal Answer Key 2025 has been released. Applicants can raise objections in OSSC JE answer key till 06 June 2025.
-> OSSC JE prelim Exam 2025 was held on 18th May 2025.(Advt. No. 1233/OSSC ).
-> The OSSC JE 2024 Notification was released for 759 vacancies through OSSC CTSRE 2024.
-> The selection is based on the written test. This is an excellent opportunity for candidates who want to get a job in the Engineering sector in the state of Odisha.
-> Candidates must refer to the OSSC JE Previous Year Papers to understand the type of questions in the examination.