Question
Download Solution PDFSarthak and Mohan are working on alternate days in a workshop. Sarthak can complete the work in 20 days while Mohan can finish in 25 days. Sarthak works on the 1st day, Mohan on the 2nd day, and so on. How much time (in days) will they take on alternate basis?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Sarthak can complete the work in 20 days
Mohan can complete the work in 25 days
Sarthak works on the 1st day, Mohan on the 2nd day, and so on.
Formula used:
Work done by Sarthak in 1 day = 1/20
Work done by Mohan in 1 day = 1/25
Combined work in 2 days = Work done by Sarthak in 1 day + Work done by Mohan in 1 day
Calculation:
Combined work in 2 days = (1/20) + (1/25)
⇒ Combined work in 2 days = (5 + 4) / 100
⇒ Combined work in 2 days = 9/100
Total work = 1
Number of such 2 day cycles required to complete the work:
⇒ Total work / Combined work in 2 days
⇒ 1 / (9/100)
⇒ 100/9 ≈ 11 cycles
Work done in 11 cycles or 22 days = 11 × 9/100 = 99/100
Remaining work = 1 - 99/100 = 1/100
Now, Sarthak complete this work in 20/100 = 1/5.
Total days = 22 1/5.
∴ The correct answer is option (3).
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