Swept-out voltage in PIN diode happens when the PIN diode is

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  1. Forward biased and the thickness of the depletion layer decreases till I-region becomes free of mobile carriers

  2. Reverse biased and the thickness of the depletion layer increases till I-region becomes free of mobile carriers

  3. Forward biased and the thickness of the depletion layer increases till I-region becomes free of mobile carriers

  4. Reverse biased and the thickness of the depletion layer decreases till I-region becomes free of mobile carriers.

Answer (Detailed Solution Below)

Option 2 :

Reverse biased and the thickness of the depletion layer increases till I-region becomes free of mobile carriers

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Detailed Solution

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PIN Diode:

  • It’s a special type of diode that contains an undoped intrinsic semiconductor between the p-type and n-type regions.
  • The intrinsic layer does not conduct electric current well.

 

F2 Shubham.B 17-09-20 Savita D 2

 

F2 Shubham.B 17-09-20 Savita D 3

  • PIN Diode is an inferior rectifier but widely suitable for switches, attenuators, etc.


PIN diode with different biasing:

Forward Bias:

  • The Depletion region reduces, resulting in the flow of current.
  • Acts as a variable resistance in the forward bias.
  • A High electric field developed across the junction and this speeds up the transport of carriers.


Reverse Bias:

1) Width of the depletion region increases.

2) At a certain voltage, the entire intrinsic layer will be swept out of charge carriers. This is called

“Swept out” voltage.

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