The equivalent resistance of the resistances (two) joined in parallel is 6/5 Ω. When one of the resistance wire is broken, the effective resistance becomes 2Ω. The resistance of the wire that got broken was :

Question

Question

This question was previously asked in

HTET TGT Science 2021 Official Paper

Answer 1

Concept:

For the resistance connected in series, the equivalent resistance is:

⇒ Req = R1 + R2 ------ (1)

For the resistance connected in parallel combination, the equivalent resistance,

----(2)

Calculation:

Given:

Case-I:

Case-II:

Let's assume R1 got broken, therefore R2 = 2Ω

For parallel combination, Req = 6/5 Ω, R2 = 2Ω as given above;

00

∴ R1 = 3Ω