Question
Download Solution PDFThe series \(\sum_{n=1}^{\infty} \frac{(-1)^n \sin n x}{n^{\log _e n}},\) \(x ∈ \mathbb{R}\) converges
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Mn test:
let an be series of real number then
\(\sum_{n=1}^{\infty} |an| \leq\)| Mn |
if Mn Is convergent then an is convergent
Calculation:
here
|an | = \(\sum_{n=1}^{\infty} \frac{ \sin n x}{n^{\log _e n}} \leq \) \(\frac{1}{n^{\log _e n}}\)
| an | \(\leq\) \(\frac{1}{n^2}\)
convergent for all x belong R .
Hence option (4) is correct
Last updated on Jun 5, 2025
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