The shear force at the point of contraflexure in the beam shown below is

Question

Question

This question was previously asked in

UKPSC AE Civil 24 April 2022 Official Paper I

Answer 1

Explanation:
F2 Vinanti Engineering 29.05.23 D2

∑M = 0

⇒ RB × L + M = 0

⇒ \({R_B} = \frac{-M}{L}\)

∑Fy = 0

⇒RA + RB = 0

So, R_A = M/L

The SED & BMD will work like this.

F5 Madhuri Engineering 30.06.2022 D10

So, the shear force at the point of contra flexure (C) is M/L