Two containers X and Y contain a mixture of milk and water. In container X, the ratio of milk to water is 5:2. In container Y, the ratio of milk to water is 3:4. The mixtures from X and Y are mixed together in the ratio 7:5 respectively to form a new mixture. How much milk is present in 84 liters of the new mixture?

Question

Question

This question was previously asked in

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 2)

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Answer 1

Given:

Container X has milk : water = 5 : 2

Container Y has milk : water = 3 : 4

Mixtures from X and Y are mixed in the ratio 7 : 5

Total final mixture = 84 liters

Total parts of mixture:

7 parts from X and 5 parts from Y

→ Total = 7 + 5 = 12 parts

So,

Mixture from X = (7/12) × 84 = 49 liters

Mixture from Y = (5/12) × 84 = 35 liters

Milk in each container

Container X:

Ratio 5:2 → Total parts = 7

Milk part = (5/7) × 49 = 35 liters

Container Y:

Ratio 3:4 → Total parts = 7

Milk part = (3/7) × 35 = 15 liters

Total milk in the new mixture:

Milk = 35 + 15 = 50 liters

Thus, the correct answer is 50 litres.