With respect to the epicyclic gear train shown in the figure below, A has 75 teeth and B has 25 teeth; A is fixed and arm C makes 5 revolutions:

The number of revolutions made by B is

This question was previously asked in
ESE Mechanical 2016 Paper 2: Official Paper
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  1. 10
  2. 15
  3. 20
  4. 25

Answer (Detailed Solution Below)

Option 3 : 20
Free
ST 1: UPSC ESE (IES) Civil - Building Materials
20 Qs. 40 Marks 24 Mins

Detailed Solution

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Concept:

The velocity ratio between two mating gears is given by

Where ω is the angular velocity and T is the number of teeth. 

Calculation:

The given gear train is an epicyclic gear train 

Sr. No.

Condition of motion

Revolutions of elements

Arm C

Gear A

Gear B

1

Arm fixed, gear A rotates through + 1 (CCW)

0

+1

2

Arm fixed, gear A rotates through + x revolutions

0

+x

3

Add +y revolutions to all elements

+y

+y

+y

4

Total Motion

+y

x + y

 

Given TA = 75, TB = 25, NC = y = 5

NA = 0 = x + y ⇒ x = -y

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