A body of weight 100 N is lying on a rough horizontal surface, and the horizontal force of 50 N is applied on the body as shown in the figure, which is just enough to move the body. What will be the coefficient of friction? 

F2 ENG Savita 04-1-24 D3

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SSC JE Mechanical 11 Oct 2023 Shift 2 Official Paper-I
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  1. 0.4
  2. 0.6
  3. 0.5
  4. 0.3

Answer (Detailed Solution Below)

Option 3 : 0.5
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Concept-

Friction-

  • Sliding friction can be defined as the resistance created by any two objects when sliding against each other.
  • This friction is also known as kinetic friction and is defined as the force that is needed to keep a surface sliding along another surface.
  • It depends on two variables- one is material and the other is the weight of the object. Any change in the surface area in contact does not change the sliding friction. 
  • The equation for sliding force includes the coefficient of sliding friction times the normal force.

F2 ENG Savita 04-1-24 D3

Fs = μFn 

Where FS =  force of sliding  friction,Fn = normal force , μ = Coefficient of sliding friction

Given data and calculation-

Body weight = Fn = 100 N

Friction force = 50 N

Coefficient of friction = \(\frac{50}{100}\) = 0.5

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