A can do a piece of work in 30 days, B in 50 days and C in 40 days. If A is assisted by B on one day and by C on the next day alternately, the work will be completed in:

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Question

This question was previously asked in

SSC CHSL (2022) Tier-II Official Paper (Held On: 26 Jun, 2023 Shift 1)

Answer 1

Calculation:

Total work = LCM of (30, 50, 40) = 600 unit

Now, efficiency of A = 20 unit, B = 12 unit, and C = 15 unit

Work done on 1st day (A + B) = 20 + 12 = 32 unit

Work done on 2^nd day (A + C) = 20 + 15 = 35 unit

So, in every 2 days they done (35 + 32) = 67 unit work

Now, in 17 days they done (67 × 8) + 32 = 568 unit

Remaining (600 - 568) = 32 unit of work done by (A + C) in 32/35 days

So, the work will be complete in 17 + 32/35 = \(17\frac{32}{35}\) days

∴ The correct answer is \(17\frac{32}{35}\) days