Question
Download Solution PDFA coil of inductance L henry is connected in parallel with an R Ω resistor. The current flowing through resistance and inductance is IR and IL , respectively. What is the value of the current drawn from the supply?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFParallel RL circuit
In a resistor, the current is in the same phase as the voltage.
\(I_R={V\over R}\angle0\)
In an inductor, the current lags voltage by 90°
\(I_L={V\over j\omega L}={V\over \angle 90\space \omega L}\)
\(I_L={V\over \omega L}\angle{-90}=-jI_L\)
The supply current is:
I = IR - j IL
The magnitude of the supply current is:
\(I=\rm \sqrt{I_R^2+I_L^2}\)
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