Question
Download Solution PDFA DC generator delivers a 30-A current to a load at 120 V by consuming 4500 J/s of mechanical energy. Determine the efficiency of the generator.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The ratio of the Electrical power output (Pe) to the line to the Mechanical power input (Pm) to the shaft is called the Efficiency of the Generator.
Efficiency, \(η = {P_e \over P_m }\)
Calculation:
Given,
Current delivered to load, I = 30 A
Voltage at the load, V = 120 V
Mechanical power input, Pm = 4500 J/s = 4500 W
Electrical power output, Pe = V × I = 120 × 30 = 3600 W
From concept,
\(\eta = {3600 \over 4500}\) = 0.8
= 80 % (In percentage)
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