Question
Download Solution PDFA PCM system uses a uniform quantizer followed by a 7-bit binary encoder. The bit rate of the system is equal to 50 × 106 bits/sec. What is the maximum message signal bandwidth for which the system operates satisfactorily?
This question was previously asked in
UPSC IES Electrical 2022 Prelims Official Paper
Answer (Detailed Solution Below)
Option 1 : 3.57 MHz
Free Tests
View all Free tests >
ST 1: UPSC ESE (IES) Civil - Building Materials
6.3 K Users
20 Questions
40 Marks
24 Mins
Detailed Solution
Download Solution PDFConcept:
The bit rate is given by:
r = N × fs
where, r = Bit rate
N = No. of bit
fs = Sampling frequency
The maximum message signal bandwidth is given by:
\(BW={f_s\over 2}\)
Calculation:
Given, r = 50 × 106 bits/sec
N = 7
\(f_s={50\times 10^6\over 7}\)
fs = 7.14 MHz
\(BW={7.14\over 2}\)
BW = 3.57 MHz
Latest UPSC IES Updates
Last updated on May 28, 2025
-> UPSC ESE admit card 2025 for the prelims exam has been released.
-> The UPSC IES Prelims 2025 will be held on 8th June 2025.
-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.
-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.
India’s #1 Learning Platform
Start Complete Exam Preparation
Daily Live MasterClasses
Practice Question Bank
Mock Tests & Quizzes
Trusted by 7.2 Crore+ Students