A single phase load of 100 KVA is delivered at 2000 V over a transmission line having R = 1.4 Ω and X = 0.8 Ω, when the power factor of load is unity, the voltage at sending end is

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ISRO (VSSC) Technical Assistant Electrical 2017 Official Paper
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  1. 1680.3 V
  2. 2980.1 V
  3. 2068.3 V
  4. 2070.4 V

Answer (Detailed Solution Below)

Option 4 : 2070.4 V
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Detailed Solution

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Concept:

In a single phase transmission line

VS = VR + IL∠ϕ Z

Where,

VS = Sending end voltage

VR = Receiving end voltage

IL = Current flowing through the transmission line

Z = Impedance of line

ϕ = Phase angle

Calculation:

Given-

SL = 100 kVA

VR = 2000 V

cos ϕ = 1, ϕ = 0°

Z = R + j X = 1.4 +j 0.8

|IL|= 100 x 103 / 2000 = 50 A

IL ∠ϕ = 50 ∠0°

Now sending end voltage is

VS = 2000 + 50 ∠0° (1.4 +j 0.8)

VS = 2000 + 50(cos0° + sin0°)(1.4 +j 0.8)

VS = 2000 + 70 + j40

VS = 2070 + j40

VS = 2070.40∠1.1°

|V­S| = 2070.40 V

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