Consider the nuclear reaction

₉₂X²³⁴ + β + α → Y + γ + 2β⁺   ;  Y is

Concept:

Nuclear reaction:

• A nuclear reaction is a process in which two nuclei, or more nuclei and other external subatomic particles collide with each other and form one or more new nuclei. 

Explanation:

For the nuclear reaction

92X234 + β + α → Y + γ + 2β⁺, 

• α (alpha) particle is a positively charged particle with 2 protons and 2 neutrons. It is represented as ₂He⁴ or ₂α⁴.
• β (beta) particle is negatively charged. It is represented as _-1e⁰. Whereas β⁺ (positron) particle is a positively charged species and represented as ₁e0. γ particle has no charge.
• So, for the nuclear reaction

92X234 + β + α → Y + γ + 2β⁺

• The reaction can be represented as

92X234 + -1e0 + 2He4 → 91Y238 + ₀γ⁰ + 2 ​1e0

• When 92X234 nuclei collide with -1e0 and 2He4 nuclei, the mass number and atomic number increase by 4 and 1 units. The mass number and the atomic number of resulting nuclei will be

=234+4 =238,
and the atomic number will be
=92+1 =93.

• Now after the collision, it forms Y and two β+ (positron) particles. The release of two β+ (positron) particles will decrease the atomic number by two units, whereas the mass number will be unchanged. So, the atomic number will be

=93-2 =91
and the mass number will be 238.

• Thus, Y will be 91Y238

​Conclusion:

For the nuclear reaction

92X234 + β + α → Y + γ + 2β+ Y is 91Y238^​.