Question
Download Solution PDFएक लम्बवत फेंकी गयी गेंद 10 sec. बाद पृथ्वी पर लौट आती है। फेंके जाने की गति बताइए? (यदि g = 10m/s2)
Answer (Detailed Solution Below)
Detailed Solution
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हम जानते हैं कि गेंद को अधिकतम ऊँचाई तक पहुँचने में लगा समय जमीन पर लौटने में लगे कुल समय का आधा होता है। अत: गेंद 5 सेकंड के बाद अधिकतम ऊंचाई पर पहुंच गई।
अत: वेग के लिए गति के समीकरण के सूत्र का प्रयोग करना अर्थात
v = u + at
चूंकि अधिकतम ऊंचाई पर गेंद का वेग शून्य होगा।
तो, v = 0
0 = u -10×5
u = 50 m/s
सही उत्तर विकल्प "2" है
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