Question
Download Solution PDFएक निकाय 5 मिनट में 70°C से 40°C तक ठंडा होता है। तो 50°C से 20°C तक ठंडा होने में इसके द्वारा लिए गए समय की गणना कीजिए, वायुमंडल का तापमान 10°C है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
न्यूटन के शीतलन के नियम का प्रयोग करने पर,
शीतलन की दर,
\(\frac{dT}{dt} = K[\frac{T_i+T_f}{2} -T_o]\)
जहाँ Ti = प्रारंभिक तापमान, Tf = अंतिम वायुमंडलीय तापमान।
\(\frac{Ti - T_f}{t} = K[\frac{T_i +T_f}{2} - T_o]\)
गणना:
दिया गया है Ti = 70oC, Tf = 40oC, t = 5 मिनट
\(\frac{70-40}{5} = K[\frac{70+40}{2} - 10]\)
6 = K × 45
K = 6/45
दूसरी स्थिति में शीतलन के नियम को लागू करने पर
\(\frac{50-20}{t} = K[\frac{50+20}{2} - 10]\)
\(\frac{30}{t} = \frac{6}{45}\times 25\)
\(t = \frac{30\times 45}{6\times 25}\) = 9 मिनट
t = 9 मिनट
अतः सही विकल्प 9 मिनट है।
Last updated on Jun 19, 2025
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