Question
Download Solution PDFएक अवतल दर्पण 5 सेमी पर रखी किसी वस्तु का 3 गुना आवर्धित वास्तविक प्रतिबिंब उत्पन्न करता है। तो दर्पण के सामने से कितनी दूरी पर प्रतिबिंब दिखाई देगा?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसही उत्तर विकल्प 1 अर्थात 15 सेमी है।
- हम जानते हैं कि आवर्धन (m) = (-v/u) = hi/ho
- प्रश्न के अनुसार u = (- 5 सेमी) (ऋणात्मक चिन्ह प्रयुक्त किया है क्योंकि निर्मित प्रतिबिंब वास्तविक प्रतिबिंब है)
- hi = 3ho
- अत: -v/u = 3ho/ho
- -v/u = 3 या-v = 3u
- v = - 3 (u) = - 3 × - 5 = 15 सेमी
Last updated on Jun 16, 2025
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