Question
Download Solution PDFएक R-L श्रेणी परिपथ, जहाँ R = 10 Ω और L = 0.056 H, 50 Hz आवृत्ति की AC आपूर्ति से जुड़ा है। परिपथ की प्रतिबाधा का परिमाण है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा
श्रेणी RL परिपथ की प्रतिबाधा निम्न द्वारा दी जाती है:
\(Z=R+jX_L\)
\(Z=R+jω L\)
प्रतिबाधा का परिमाण है:
\(\left | Z \right |=\sqrt{R^2+X_L^2}\)
गणना
दिया गया है, R = 10 Ω और L = 0.056 H
f = 50 Hz
ω = 2πf = 314 रेडियन
XL = ω × L
XL = 314 × 0.056 = 17.584 Ω
\(\left | Z \right |=\sqrt{(10)^2+(17.584)^2}\)
\(\left | Z \right |=20.23\space \Omega\)
Last updated on Jun 16, 2025
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