(cos π/9 + i sin π/9 )¹⁸का मूल्यांकन कीजिए।

Question

Question

Answer 1

संकल्पना:

\({e^{i\; ⋅ \;\theta }} = \cos \theta + i\sin \theta \)

गणना:

चूँकि हम जानते हैं कि,

\({e^{i\; ⋅ \;\theta }} = \cos \theta + i\sin \theta \)

⇒ (cos π/9 + i sin π/9 )18

= [e^i ⋅ π/9]¹⁸ = e^{i ⋅ 2π}

⇒ e^{i ⋅ 2π}

= cos 2π + i sin 2π = 1