यदि K + \(\frac{1}{K}\) + 2 = 0 और K < 0 है, तो  K11\(\frac{1}{K^4}\) का मान क्या है?

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SSC CGL 2022 Tier-I Official Paper (Held On : 13 Dec 2022 Shift 1)
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  1. 0
  2. -2
  3. -1
  4. -17

Answer (Detailed Solution Below)

Option 1 : 0
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दिया गया है:

K + \(\frac{1}{K}\) + 2 = 0 और K < 0

प्रयुक्त अवधारणा:

(a2 + 2ab + b2) = (a + b)2

गणना:

K + \(\frac{1}{K}\) + 2 = 0

⇒ k2 + 2k + 1 = 0

⇒ (k + 1)2 = 0

⇒ (k + 1) = 0

⇒ k = -1

अब,  K11 + \(\frac{1}{K^4}\)

⇒ (-1)11 + \(\frac{1}{(-1)^4}\)

⇒ -1 + 1

⇒ 0

∴  K11 + \(\frac{1}{K^4}\) का मान 0 है।

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