Question
Download Solution PDFयदि K + \(\frac{1}{K}\) + 2 = 0 और K < 0 है, तो K11 + \(\frac{1}{K^4}\) का मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
K + \(\frac{1}{K}\) + 2 = 0 और K < 0
प्रयुक्त अवधारणा:
(a2 + 2ab + b2) = (a + b)2
गणना:
K + \(\frac{1}{K}\) + 2 = 0
⇒ k2 + 2k + 1 = 0
⇒ (k + 1)2 = 0
⇒ (k + 1) = 0
⇒ k = -1
अब, K11 + \(\frac{1}{K^4}\)
⇒ (-1)11 + \(\frac{1}{(-1)^4}\)
⇒ -1 + 1
⇒ 0
∴ K11 + \(\frac{1}{K^4}\) का मान 0 है।
Last updated on Jul 12, 2025
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