Question
Download Solution PDFदी गई आकृति में, PQ वृत्त के केंद्र 'O' से गुजरने वाली एक जीवा है। ∠PQS की गणना कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFप्रयुक्त अवधारणा:
चक्रीय चतुर्भुज के सम्मुख कोणों का योग 180° होता है।
∠PSQ = 90° क्योंकि कोण अर्धवृत्त में है।
गणना:
∠SPQ = 180° - 110° = 70° ( चक्रीय चतुर्भुज के सम्मुख कोणों का योग 180° है)
अब, त्रिभुज PQS में।
∠PSQ = 90° (अर्धवृत्त में कोण)
∠PQS = 180° - ( ∠PSQ +∠QPS)
⇒ 180° - (90° + 70°) = 20°
∴ सही विकल्प 3 है
Last updated on Jul 21, 2025
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