एक दीर्घ-शंट यौगिक जनित्र में विभिन्न शाखा में वोल्टेज और धारा निम्न नेटवर्क में दिया गया है। तब उत्पन्न EMF निर्धारित करें।

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SSC JE EE Previous Paper 10 (Held on: 10 Dec 2020)
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  1. 510 V
  2. 502.2 V
  3. 504.16 V
  4. 512.2 V

Answer (Detailed Solution Below)

Option 3 : 504.16 V
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Detailed Solution

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अवधारणा:

एक दीर्घ-शंट यौगिक जनित्र में:

F1 Jai 18.1.21 Pallavi D2

यहाँ, Vt = टर्मिनल वोल्टेज (V)

Il = लाइन धारा (A)

Rsf = श्रृंखला क्षेत्र प्रतिरोध (Ω)

Ra = आर्मेचर प्रतिरोध (Ω)

Rshf = शंट छेत्र प्रतिरोध (Ω)

Ish = शंट धारा (A)

Ia = आर्मेचर धारा (A)

Eg = उत्पन्न EMF (V)

सूत्र:

\({I_{sh}}=\frac{{{V_t}}}{{{R_{shf}}}}\)

I= Ish + Il

Eg = Vt + Ia(Ra + Rsf)

गणना:

F1 Jai 18.1.21 Pallavi D3

दिया हुआ है कि:

Ish = 2 A

Il = 50 A

Vt = 500 V

Ra = 0.05 Ω

Rsf = 0.03 Ω

Rshf = 250 Ω

Ia = Ish + Il

Ia = 2 + 50 = 52 A

Eg = Vt + Ia(Ra + Rsf)

Eg = 500 + 52(0.05+0.03)

Eg = 504.16 V

Important Points

एक लघु शंट यौगिक जनित्र में:

F1 Jai 18.1.21 Pallavi D4

Va = Vt + IlRsf

Ia = Ish + Il

\({I_{sh}}=\frac{{{V_t}}}{{{R_{shf}}}}\)

Eg = Va + IaRa

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