Question
Download Solution PDFदो शाफ्ट, A और B, एक ही पदार्थ के बने हैं। यदि A का व्यास B के व्यास का तीन गुना है, तो A द्वारा प्रेषित किया जा सकने वाला टॉर्क होगा:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसिद्धांत:
एक वृत्ताकार शाफ्ट द्वारा प्रेषित टॉर्क इसके व्यास के घन के समानुपाती होता है, जो सूत्र द्वारा दिया गया है:
\( T = \frac{\pi}{16} \cdot τ \cdot d^3 \)
दिया गया है:
- शाफ्ट A और B एक ही पदार्थ के हैं → समान अपरूपण प्रतिबल \(\tau\)
- A का व्यास B के व्यास का 3 गुना है → dA = 3dB
गणना:
\( \frac{T_A}{T_B} = \left( \frac{d_A}{d_B} \right)^3 = 3^3 = 27 \)
Last updated on Jun 7, 2025
-> RRB JE CBT 2 answer key 2025 for June 4 exam has been released at the official website.
-> Check Your Marks via RRB JE CBT 2 Rank Calculator 2025
-> RRB JE CBT 2 admit card 2025 has been released.
-> RRB JE CBT 2 city intimation slip 2025 for June 4 exam has been released at the official website.
-> RRB JE CBT 2 Cancelled Shift Exam 2025 will be conducted on June 4, 2025 in offline mode.
-> RRB JE CBT 2 Exam Analysis 2025 is Out, Candidates analysis their exam according to Shift 1 and 2 Questions and Answers.
-> The RRB JE Notification 2024 was released for 7951 vacancies for various posts of Junior Engineer, Depot Material Superintendent, Chemical & Metallurgical Assistant, Chemical Supervisor (Research) and Metallurgical Supervisor (Research).
-> The selection process includes CBT 1, CBT 2, and Document Verification & Medical Test.
-> The candidates who will be selected will get an approximate salary range between Rs. 13,500 to Rs. 38,425.
-> Attempt RRB JE Free Current Affairs Mock Test here
-> Enhance your preparation with the RRB JE Previous Year Papers.