Question
Download Solution PDFHow many wattmeter(s) is required to measure 6 – phase, 6 – wire without neutral wire system?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFMeasurement of power
According to Blondel's Theorem, for the measurement of power in n-phase, n-wire without neutral, (n-1) wattmeters are required.
Therefore, for a 6-phase, 6-wire without a neutral system, a 5-wattmeter is required.
For measurement of power in n-phase, (n+1) wire with neutral, n wattmeters are required.
Additional Information For the measurement of power in the 3ϕ system, 2 wattmeters are required.
The readings of both the wattmeters are given by:
\(W_1=V_LI_Lcos(30+ϕ)\)
\(W_2=V_LI_Lcos(30-ϕ)\)
The total power is given by:
\(W=W_1+W_2=\sqrt{3}V_LI_L\space cosϕ\)
where VL and IL are line voltage and line current respectively and cosϕ is the power factor.
Last updated on May 9, 2025
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