Identify the product in the following reaction :

Explanation:-

The reaction involves the reduction of a carbonyl compound (specifically a ketone) using the Clemmensen reduction method. The Clemmensen reduction is used to reduce ketones (or aldehydes) to alkanes. The reagents used are zinc amalgam (Zn-Hg) and hydrochloric acid (HCl).

The given reactant is:

\(\text{4-methylacetophenone} \ (C_6H_5COCH_3)\)

The Clemmensen reduction reduces the carbonyl group (C=O) to a methylene group (CH2). 

Here is the reaction:

\(\text{C}_6\text{H}_5\text{COCH}_3 \xrightarrow{\text{Zn-Hg, HCl}} \text{C}_6\text{H}_5\text{CH}_2\text{CH}_3\)

The carbonyl group (C=O) in 4-methylacetophenone is reduced to an ethyl group (CH2).

So, the product of the reaction is:

\(\text{4-ethyl toluene (p-ethyltoluene)}\)

1. The first option shows a compound with two hydroxyl groups attached to the benzene ring, which is incorrect.
2. The second option shows the starting material, which is incorrect.
3. The third option shows a compound with a hydroxyl group attached to the benzene ring, which is incorrect.
4. The fourth option shows 4-ethyl toluene (p-ethyltoluene), which is the correct product.

Thus, the correct answer is 4