If |3x - 5| ≤ 2 then

  1. \(\rm -1 \le x \le \dfrac{7}{3}\)
  2. \(\rm 1 \le x \le \dfrac{7}{3}\)
  3. \(\rm 1 \le x \le \dfrac{9}{3}\)
  4. \(\rm -1 \le x \le \dfrac{9}{3}\)

Answer (Detailed Solution Below)

Option 2 : \(\rm 1 \le x \le \dfrac{7}{3}\)
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Detailed Solution

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Concept:

If |x| ≤ a then - a ≤ x ≤ a

 

Calculations:

Given , |3x - 5| ≤ 2 

⇒ - 2 ≤ 3x - 5 ≤ 2

⇒ - 2 + 5 ≤ 3x  ≤ 2 + 5 

⇒ 3 ≤ 3x  ≤ 7

\(\rm 1 \le x \le \dfrac{7}{3}\) 

Hence, if |3x - 5| ≤ 2 then then \(\rm 1 \le x \le \dfrac{7}{3}\)

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