Question
Download Solution PDFIf a soil uniformity coefficient is less than 3, coefficient of curvature greater than 3 and having more than half of coarse fraction (+75 micron i.e. retained on 75 microns IS sieve) Is smaller than 4.75 mm IS sieve, then the classification of the soil is.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Soil classification:
% of fraction passing through 75 μ sieve |
Gravel (G) ( > 4.75 mm) |
Sand (S) ( 425 𝛍 to 4.75 mm) |
Remarks |
||
|
Well Graded (W) If Cu > 4 Cc = 1 to 3 |
Poorly Graded (P) (Else) |
Well Graded (W) If Cu > 6 Cc = 1 to 3 |
Poorly Graded (P) (else) |
|
1. p < 5 % |
GW |
GP |
SW |
SP |
Gradation only governs the properties |
2. p (5 to 12 %) |
GW – GC or GW – GM |
GP – GC or GP – GM |
SW – SC or SW – SM |
GP – GC or GP - GH |
Dual symbol check the presence of either clay (C) or silt (M), using plasticity chart |
3. p > 12% |
IP < 7 % |
IP > 7 % |
IP < 4 % |
IP > 4 % |
The presence of fine particles dominate the soil characteristics |
GM |
GC |
SM |
SC |
Here,
Cu - Coefficient of uniformity
Cc - Coefficient of curvature
Explanation:
Given,
More than half of the coarse fraction < 4.75 mm IS sieve → Sand
Cu < 3 → Poorly graded
Hence,
The given soil is classified as Poorly graded sand.
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