Question
Download Solution PDFIf the height of a hallow cone is 10 m, what will the distance of center of gravity from its vertex?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The distance of the center of gravity (CG) from the vertex of a hollow cone is given by the formula:
\(\text{Distance from vertex} = \frac{2h}{3}\)
where \(h\) is the height of the cone.
Calculation:
Given:
- Height of the hollow cone, \(h = 10 \, \text{m}\)
Using the formula for the distance of the center of gravity from the vertex:
\(\text{Distance from vertex} = \frac{2h}{3}\)
Substitute the given value of \(h\):
\(\text{Distance from vertex} = \frac{2 \times 10}{3} = \frac{20}{3} \approx 6.67 \, \text{m}\)
The distance of the center of gravity from the vertex is 6.67 m
Last updated on Jun 2, 2025
-> HPCL Engineer 2025 notification has been released on June 1, 2025.
-> A total of 175 vacancies have been announced for the HPCL Engineer post in Civil, Electrical, Mechanical, Chemical engineering.
-> HPCL Engineer Online application will be activated from 1st June 2025 to 30th June 2025.
-> Candidates with a full-time engineering discipline in the relevant stream are eligible to apply.
-> The selection will be based on a Computer Based Test Group Task and/or Interview. Prepare for the exam using HPCL Engineer Previous Year Papers.